What are the solutions to the equation b^2-8b+15=0 ?

The solutions to the equation b^2-8b+15=0 are b=5,b=3

Find the zeros of b^2-8b+15=0

The zeros of b^2-8b+15=0 are b=5,b=3

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b^{2} - 8 b + 15 = 0

b = 5, b = 3

Solution steps

b^{2} - 8 b + 15 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

b_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, b_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

b = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

b = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

b = 5, b = 3

t^{2} - 2 t + 1 = 36

x, x^{2} + y^{2} + 6 x - 4 y + 13 = 0

3 t^{2} - t - 6

4 x^{2} + 1.32 x - 0.33 = 0

x, x^{2} - 121 = 0

What are the solutions to the equation b^2-8b+15=0 ?
The solutions to the equation b^2-8b+15=0 are b=5,b=3
Find the zeros of b^2-8b+15=0
The zeros of b^2-8b+15=0 are b=5,b=3