What are the solutions to the equation (2x+3)^2=5 ?

The solutions to the equation (2x+3)^2=5 are x=(sqrt(5)-3)/2 ,x=(-sqrt(5)-3)/2

Find the zeros of (2x+3)^2=5

The zeros of (2x+3)^2=5 are x=(sqrt(5)-3)/2 ,x=(-sqrt(5)-3)/2

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(2 x + 3)^{2} = 5

x = \frac{5 - 3}{2}, x = \frac{- 5 - 3}{2}

Decimal Notation

x = - 0.38196 \dots, x = - 2.61803 \dots

Solution steps

(2 x + 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 5 : x = \frac{5 - 3}{2}

Solve

2 x + 3 = - 5 : x = \frac{- 5 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{5 - 3}{2}, x = \frac{- 5 - 3}{2}

2 x^{2} - 21 x - 11 = 0

x, y^{2} = \frac{1}{2} x^{2}

m^{2} + 21 = m

4 x^{2} + 11 x = 20

4 q^{2} - 15 = \frac{1 + 4 q}{30}

What are the solutions to the equation (2x+3)^2=5 ?
The solutions to the equation (2x+3)^2=5 are x=(sqrt(5)-3)/2 ,x=(-sqrt(5)-3)/2
Find the zeros of (2x+3)^2=5
The zeros of (2x+3)^2=5 are x=(sqrt(5)-3)/2 ,x=(-sqrt(5)-3)/2