What are the solutions to the equation x^2-x=3x ?

The solutions to the equation x^2-x=3x are x=4,x=0

Find the zeros of x^2-x=3x

The zeros of x^2-x=3x are x=4,x=0

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x^{2} - x = 3 x

x = 4, x = 0

Solution steps

x^{2} - x = 3 x

Move

3 x

to the left side

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

4 c^{2} - 1

∣ 2 a + 7 ∣ + 7 = 4

- 1 - \frac{2}{3}

ln (49)

\frac{( 1.75 \cdot 1 0 ^{- 10} )}{0.06}

What are the solutions to the equation x^2-x=3x ?
The solutions to the equation x^2-x=3x are x=4,x=0
Find the zeros of x^2-x=3x
The zeros of x^2-x=3x are x=4,x=0