What are the solutions to the equation m^2-2m+10=0 ?

The solutions to the equation m^2-2m+10=0 are m=1+3i,m=1-3i

Find the zeros of m^2-2m+10=0

The zeros of m^2-2m+10=0 are m=1+3i,m=1-3i

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m^{2} - 2 m + 10 = 0

m = 1 + 3 i, m = 1 - 3 i

Solution steps

m^{2} - 2 m + 10 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 10 : 6 i

m_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 6 i}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 6 i}{2 \cdot 1}

m = \frac{- ( - 2 ) + 6 i}{2 \cdot 1} : 1 + 3 i

m = \frac{- ( - 2 ) - 6 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

m = 1 + 3 i, m = 1 - 3 i

x, (x - 6)^{2} + (y + 4)^{2} + z^{2} = 25

x^{2} = 7 x - 6

- x^{2} - 10 x = 34

6 - x^{2} = 3 x

2 - 4 x^{2} = - 110

What are the solutions to the equation m^2-2m+10=0 ?
The solutions to the equation m^2-2m+10=0 are m=1+3i,m=1-3i
Find the zeros of m^2-2m+10=0
The zeros of m^2-2m+10=0 are m=1+3i,m=1-3i