What are the solutions to the equation x^2+4=-2x+3 ?

The solutions to the equation x^2+4=-2x+3 are x=-1

Find the zeros of x^2+4=-2x+3

The zeros of x^2+4=-2x+3 are x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 = - 2 x + 3

x = - 1

Solution steps

x^{2} + 4 = - 2 x + 3

Move

3

to the left side

x^{2} + 1 = - 2 x

Move

2 x

to the left side

x^{2} + 1 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

- x^{2} + 4 x + 3 = x - 1

x^{2} = x + 4

3^{2} = x^{2} + 2^{2}

(x - \frac{\frac{7}{6}}{2})^{2} - (\frac{\frac{- 7}{6}}{2})^{2} - \frac{1}{4} = 0

(x + 3)^{2} - 2 = 2 x (x + 2) + x + 8

What are the solutions to the equation x^2+4=-2x+3 ?
The solutions to the equation x^2+4=-2x+3 are x=-1
Find the zeros of x^2+4=-2x+3
The zeros of x^2+4=-2x+3 are x=-1