What are the solutions to the equation n^2+3n-28=0 ?

The solutions to the equation n^2+3n-28=0 are n=4,n=-7

Find the zeros of n^2+3n-28=0

The zeros of n^2+3n-28=0 are n=4,n=-7

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n^{2} + 3 n - 28 = 0

n = 4, n = - 7

Solution steps

n^{2} + 3 n - 28 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

n_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 3 + 11}{2 \cdot 1}, n_{2} = \frac{- 3 - 11}{2 \cdot 1}

n = \frac{- 3 + 11}{2 \cdot 1} : 4

n = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

n = 4, n = - 7

3 + 5 x - 2 x^{2} = 0

6 x^{2} + 9 x + 2 = - 2 - 4 x - 3 x^{2}

6 p - 6 = p^{2}

2 x^{2} - 9 x - 2 = - 6

\frac{( 2 x \cdot ( x - 4 ) )}{3} + \frac{x}{5} = \frac{5}{3}

What are the solutions to the equation n^2+3n-28=0 ?
The solutions to the equation n^2+3n-28=0 are n=4,n=-7
Find the zeros of n^2+3n-28=0
The zeros of n^2+3n-28=0 are n=4,n=-7