What are the solutions to the equation 4+6x-9x^2=0 ?

The solutions to the equation 4+6x-9x^2=0 are x=-(-1+sqrt(5))/3 ,x=(1+sqrt(5))/3

Find the zeros of 4+6x-9x^2=0

The zeros of 4+6x-9x^2=0 are x=-(-1+sqrt(5))/3 ,x=(1+sqrt(5))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 + 6 x - 9 x^{2} = 0

x = - \frac{- 1 + 5}{3}, x = \frac{1 + 5}{3}

Decimal Notation

x = - 0.41202 \dots, x = 1.07868 \dots

Solution steps

4 + 6 x - 9 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 9 x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 9 ) \cdot 4}{2 ( - 9 )}

6^{2} - 4 (- 9) \cdot 4 = 65

x_{1, 2} = \frac{- 6 \pm 6 5}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 5}{2 ( - 9 )}, x_{2} = \frac{- 6 - 6 5}{2 ( - 9 )}

x = \frac{- 6 + 6 5}{2 ( - 9 )} : - \frac{- 1 + 5}{3}

x = \frac{- 6 - 6 5}{2 ( - 9 )} : \frac{1 + 5}{3}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 5}{3}, x = \frac{1 + 5}{3}

(- 2 y - 1)^{2} + (y - 1)^{2} = 5

x^{2} - 16 x + 50 = 21

4 t^{2} - 19 t + 18 = 0

2 x^{2} + (2 x + 11)^{2} = x + 136

2 y^{2} - 7 y + 5 = 0

What are the solutions to the equation 4+6x-9x^2=0 ?
The solutions to the equation 4+6x-9x^2=0 are x=-(-1+sqrt(5))/3 ,x=(1+sqrt(5))/3
Find the zeros of 4+6x-9x^2=0
The zeros of 4+6x-9x^2=0 are x=-(-1+sqrt(5))/3 ,x=(1+sqrt(5))/3