What are the solutions to the equation 9x^2+17x-2=0 ?

The solutions to the equation 9x^2+17x-2=0 are x= 1/9 ,x=-2

Find the zeros of 9x^2+17x-2=0

The zeros of 9x^2+17x-2=0 are x= 1/9 ,x=-2

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9 x^{2} + 17 x - 2 = 0

x = \frac{1}{9}, x = - 2

Decimal Notation

x = 0.11111 \dots, x = - 2

Solution steps

9 x^{2} + 17 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

1 7^{2} - 4 \cdot 9 (- 2) = 19

x_{1, 2} = \frac{- 17 \pm 19}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 17 + 19}{2 \cdot 9}, x_{2} = \frac{- 17 - 19}{2 \cdot 9}

x = \frac{- 17 + 19}{2 \cdot 9} : \frac{1}{9}

x = \frac{- 17 - 19}{2 \cdot 9} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{9}, x = - 2

\frac{a - x}{b} = c (x - d)^{2}

y, x^{2} + y^{2} = x^{3}

- x^{2} + 10 = - 9 x

6 x^{2} - 72 x + 210 = 0

(3 x + 2)^{2} = (2 x + 1) (2 x - 1) - 2

What are the solutions to the equation 9x^2+17x-2=0 ?
The solutions to the equation 9x^2+17x-2=0 are x= 1/9 ,x=-2
Find the zeros of 9x^2+17x-2=0
The zeros of 9x^2+17x-2=0 are x= 1/9 ,x=-2