What are the solutions to the equation 24-9x^2=2,4-18=6 ?

The solutions to the equation 24-9x^2=2,4-18=6 are x=(sqrt(22))/3 ,x=-(sqrt(22))/3

Find the zeros of 24-9x^2=2,4-18=6

The zeros of 24-9x^2=2,4-18=6 are x=(sqrt(22))/3 ,x=-(sqrt(22))/3

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24 - 9 x^{2} = 2, 4 - 18 = 6

x = \frac{22}{3}, x = - \frac{22}{3}

Solution steps

24 - 9 x^{2} = 2, 4 - 18 = 6

Move

24

to the right side

- 9 x^{2} = - 22

Divide both sides by

- 9

x^{2} = \frac{22}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{22}{9}, x = - \frac{22}{9}

\frac{22}{9} = \frac{22}{3}

- \frac{22}{9} = - \frac{22}{3}

x = \frac{22}{3}, x = - \frac{22}{3}

Check constrains

x = \frac{22}{3}, x = - \frac{22}{3}

x, x^{2} + 4 y^{2} + z^{2} - 4 x - 8 y + 8 z + 15 = 0

h, y = a (x - h)^{2} + k

2 x^{2} + 3 x + 2

2 v^{2} - 4 v - 64 = - 2

s^{2} + 6 s + 2 = 0

What are the solutions to the equation 24-9x^2=2,4-18=6 ?
The solutions to the equation 24-9x^2=2,4-18=6 are x=(sqrt(22))/3 ,x=-(sqrt(22))/3
Find the zeros of 24-9x^2=2,4-18=6
The zeros of 24-9x^2=2,4-18=6 are x=(sqrt(22))/3 ,x=-(sqrt(22))/3