What are the solutions to the equation s^2+6s+3=0 ?

The solutions to the equation s^2+6s+3=0 are s=-3+sqrt(6),s=-3-sqrt(6)

Find the zeros of s^2+6s+3=0

The zeros of s^2+6s+3=0 are s=-3+sqrt(6),s=-3-sqrt(6)

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s^{2} + 6 s + 3 = 0

s = - 3 + 6, s = - 3 - 6

Decimal Notation

s = - 0.55051 \dots, s = - 5.44948 \dots

Solution steps

s^{2} + 6 s + 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 3 = 26

s_{1, 2} = \frac{- 6 \pm 2 6}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 6 + 2 6}{2 \cdot 1}, s_{2} = \frac{- 6 - 2 6}{2 \cdot 1}

s = \frac{- 6 + 2 6}{2 \cdot 1} : - 3 + 6

s = \frac{- 6 - 2 6}{2 \cdot 1} : - 3 - 6

The solutions to the quadratic equation are:

s = - 3 + 6, s = - 3 - 6

(x + 7)^{2} + (x - 7)^{2} = 130

16 d^{2} = 25

(x + 1)^{2} - 5 (x + 1) + 6 = 0

x^{2} + 8 x + 0 = 0

x, x^{2} + y^{2} + z^{2} + 4 x - 6 y + 2 z + 6 = 0

What are the solutions to the equation s^2+6s+3=0 ?
The solutions to the equation s^2+6s+3=0 are s=-3+sqrt(6),s=-3-sqrt(6)
Find the zeros of s^2+6s+3=0
The zeros of s^2+6s+3=0 are s=-3+sqrt(6),s=-3-sqrt(6)