What are the solutions to the equation 3x^2-29x+26=0 ?

The solutions to the equation 3x^2-29x+26=0 are x= 26/3 ,x=1

Find the zeros of 3x^2-29x+26=0

The zeros of 3x^2-29x+26=0 are x= 26/3 ,x=1

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3 x^{2} - 29 x + 26 = 0

x = \frac{26}{3}, x = 1

Decimal Notation

x = 8.66666 \dots, x = 1

Solution steps

3 x^{2} - 29 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 3 \cdot 26}{2 \cdot 3}

(- 29)^{2} - 4 \cdot 3 \cdot 26 = 23

x_{1, 2} = \frac{- ( - 29 ) \pm 23}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 23}{2 \cdot 3}, x_{2} = \frac{- ( - 29 ) - 23}{2 \cdot 3}

x = \frac{- ( - 29 ) + 23}{2 \cdot 3} : \frac{26}{3}

x = \frac{- ( - 29 ) - 23}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = \frac{26}{3}, x = 1

9 x^{2} - 12 x + 4 = - 3

x, z = x y (3 - x - y)

b^{2} + 3 b - 18 = 0

y, x^{3} + x^{2} y^{2} - 4 x - 2 y = 0

2 x^{2} + 4 x - 39 = x^{2}

What are the solutions to the equation 3x^2-29x+26=0 ?
The solutions to the equation 3x^2-29x+26=0 are x= 26/3 ,x=1
Find the zeros of 3x^2-29x+26=0
The zeros of 3x^2-29x+26=0 are x= 26/3 ,x=1