What are the solutions to the equation 1+0.2x+0.7x^2=0 ?

The solutions to the equation 1+0.2x+0.7x^2=0 are x=-1/7+i(sqrt(69))/7 ,x=-1/7-i(sqrt(69))/7

Find the zeros of 1+0.2x+0.7x^2=0

The zeros of 1+0.2x+0.7x^2=0 are x=-1/7+i(sqrt(69))/7 ,x=-1/7-i(sqrt(69))/7

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1 + 0.2 x + 0.7 x^{2} = 0

x = - \frac{1}{7} + i \frac{69}{7}, x = - \frac{1}{7} - i \frac{69}{7}

Solution steps

1 + 0.2 x + 0.7 x^{2} = 0

Multiply both sides by

10

10 + 2 x + 7 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} + 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 7 \cdot 10}{2 \cdot 7}

Simplify

2^{2} - 4 \cdot 7 \cdot 10 : 269 i

x_{1, 2} = \frac{- 2 \pm 2 69 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 2 + 2 69 i}{2 \cdot 7}, x_{2} = \frac{- 2 - 2 69 i}{2 \cdot 7}

x = \frac{- 2 + 2 69 i}{2 \cdot 7} : - \frac{1}{7} + i \frac{69}{7}

x = \frac{- 2 - 2 69 i}{2 \cdot 7} : - \frac{1}{7} - i \frac{69}{7}

The solutions to the quadratic equation are:

x = - \frac{1}{7} + i \frac{69}{7}, x = - \frac{1}{7} - i \frac{69}{7}

\frac{1}{6} n^{2} - \frac{1}{2} n - \frac{2}{3} = 0

(x + 3)^{2} + 3 x^{2} = 10 x + 8

x^{2} + 70 x - 3000 = 0

y, x^{3} + x y^{2} = 2

a, (\frac{a}{2} + r)^{2} = (\frac{a}{2} - r)^{2} + (\frac{a}{2} - r)^{2}

What are the solutions to the equation 1+0.2x+0.7x^2=0 ?
The solutions to the equation 1+0.2x+0.7x^2=0 are x=-1/7+i(sqrt(69))/7 ,x=-1/7-i(sqrt(69))/7
Find the zeros of 1+0.2x+0.7x^2=0
The zeros of 1+0.2x+0.7x^2=0 are x=-1/7+i(sqrt(69))/7 ,x=-1/7-i(sqrt(69))/7