What are the solutions to the equation 2(x-4)^2=18 ?

The solutions to the equation 2(x-4)^2=18 are x=7,x=1

Find the zeros of 2(x-4)^2=18

The zeros of 2(x-4)^2=18 are x=7,x=1

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2 (x - 4)^{2} = 18

x = 7, x = 1

Solution steps

2 (x - 4)^{2} = 18

Divide both sides by

2

(x - 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 9 : x = 7

Solve

x - 4 = - 9 : x = 1

The solutions to the quadratic equation are:

x = 7, x = 1

x^{2} + 3 x = - \frac{1}{4}

4 x^{2} = 256

0 = 3 x^{2} - 4 x - 5

m^{2} - 5 m + 3 = 0

8 y^{2} + 8 y + 2 = 0

What are the solutions to the equation 2(x-4)^2=18 ?
The solutions to the equation 2(x-4)^2=18 are x=7,x=1
Find the zeros of 2(x-4)^2=18
The zeros of 2(x-4)^2=18 are x=7,x=1