What are the solutions to the equation 2x^2+4=3x+9 ?

The solutions to the equation 2x^2+4=3x+9 are x= 5/2 ,x=-1

Find the zeros of 2x^2+4=3x+9

The zeros of 2x^2+4=3x+9 are x= 5/2 ,x=-1

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2 x^{2} + 4 = 3 x + 9

x = \frac{5}{2}, x = - 1

Decimal Notation

x = 2.5, x = - 1

Solution steps

2 x^{2} + 4 = 3 x + 9

Move

9

to the left side

2 x^{2} - 5 = 3 x

Move

3 x

to the left side

2 x^{2} - 5 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 5) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 2}

x = \frac{- ( - 3 ) + 7}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 3 ) - 7}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 1

- 2 x^{2} + 4 x + 8 = 0

3 x^{2} - (- 4 x + 7) = 2 x^{2} + 5 x - 9

x, - y (x^{2} - y) - (x + 1) (x - 1) = 0

3 w^{2} - w + 5 = 6

x^{2} - 3 x - 1 = 0

What are the solutions to the equation 2x^2+4=3x+9 ?
The solutions to the equation 2x^2+4=3x+9 are x= 5/2 ,x=-1
Find the zeros of 2x^2+4=3x+9
The zeros of 2x^2+4=3x+9 are x= 5/2 ,x=-1