What are the solutions to the equation 4(6a-3)^2+28=32 ?

The solutions to the equation 4(6a-3)^2+28=32 are a= 2/3 ,a= 1/3

Find the zeros of 4(6a-3)^2+28=32

The zeros of 4(6a-3)^2+28=32 are a= 2/3 ,a= 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (6 a - 3)^{2} + 28 = 32

a = \frac{2}{3}, a = \frac{1}{3}

Decimal Notation

a = 0.66666 \dots, a = 0.33333 \dots

Solution steps

4 (6 a - 3)^{2} + 28 = 32

Move

28

to the right side

4 (6 a - 3)^{2} = 4

Divide both sides by

4

(6 a - 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 a - 3 = 1 : a = \frac{2}{3}

Solve

6 a - 3 = - 1 : a = \frac{1}{3}

The solutions to the quadratic equation are:

a = \frac{2}{3}, a = \frac{1}{3}

c^{2} = 37

y^{2} - y = 0

x, x^{2} + y^{2} + 4 x - 2 y + 9 = 0

\frac{1}{2} x - 3 = x^{2} - 1

x, f = x^{2} - 2 x + 3 k

What are the solutions to the equation 4(6a-3)^2+28=32 ?
The solutions to the equation 4(6a-3)^2+28=32 are a= 2/3 ,a= 1/3
Find the zeros of 4(6a-3)^2+28=32
The zeros of 4(6a-3)^2+28=32 are a= 2/3 ,a= 1/3