What are the solutions to the equation 6x^2+5x-5=0 ?

The solutions to the equation 6x^2+5x-5=0 are x=(-5+sqrt(145))/(12),x=(-5-sqrt(145))/(12)

Find the zeros of 6x^2+5x-5=0

The zeros of 6x^2+5x-5=0 are x=(-5+sqrt(145))/(12),x=(-5-sqrt(145))/(12)

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6 x^{2} + 5 x - 5 = 0

x = \frac{- 5 + 145}{12}, x = \frac{- 5 - 145}{12}

Decimal Notation

x = 0.58679 \dots, x = - 1.42013 \dots

Solution steps

6 x^{2} + 5 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 5) = 145

x_{1, 2} = \frac{- 5 \pm 145}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 145}{2 \cdot 6}, x_{2} = \frac{- 5 - 145}{2 \cdot 6}

x = \frac{- 5 + 145}{2 \cdot 6} : \frac{- 5 + 145}{12}

x = \frac{- 5 - 145}{2 \cdot 6} : \frac{- 5 - 145}{12}

The solutions to the quadratic equation are:

x = \frac{- 5 + 145}{12}, x = \frac{- 5 - 145}{12}

3^{6}

x^{2} + 121 = 0

\frac{x}{11} \geq 6

\frac{5}{9} (f - 32) = 25

424 + 54

What are the solutions to the equation 6x^2+5x-5=0 ?
The solutions to the equation 6x^2+5x-5=0 are x=(-5+sqrt(145))/(12),x=(-5-sqrt(145))/(12)
Find the zeros of 6x^2+5x-5=0
The zeros of 6x^2+5x-5=0 are x=(-5+sqrt(145))/(12),x=(-5-sqrt(145))/(12)