What are the solutions to the equation x^2-14x+39=0 ?

The solutions to the equation x^2-14x+39=0 are x=7+sqrt(10),x=7-sqrt(10)

Find the zeros of x^2-14x+39=0

The zeros of x^2-14x+39=0 are x=7+sqrt(10),x=7-sqrt(10)

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x^{2} - 14 x + 39 = 0

x = 7 + 10, x = 7 - 10

Decimal Notation

x = 10.16227 \dots, x = 3.83772 \dots

Solution steps

x^{2} - 14 x + 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 39}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 39 = 210

x_{1, 2} = \frac{- ( - 14 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 10}{2 \cdot 1} : 7 + 10

x = \frac{- ( - 14 ) - 2 10}{2 \cdot 1} : 7 - 10

The solutions to the quadratic equation are:

x = 7 + 10, x = 7 - 10

x \cdot x = 1

3 x^{2} - 588 = 0

x^{2} - 2 x - 24 = 24

x^{2} - \frac{4}{9} = 0

c x^{2} + d x = c + d

What are the solutions to the equation x^2-14x+39=0 ?
The solutions to the equation x^2-14x+39=0 are x=7+sqrt(10),x=7-sqrt(10)
Find the zeros of x^2-14x+39=0
The zeros of x^2-14x+39=0 are x=7+sqrt(10),x=7-sqrt(10)