What are the solutions to the equation k^2-5k+2=0 ?

The solutions to the equation k^2-5k+2=0 are k=(5+sqrt(17))/2 ,k=(5-sqrt(17))/2

Find the zeros of k^2-5k+2=0

The zeros of k^2-5k+2=0 are k=(5+sqrt(17))/2 ,k=(5-sqrt(17))/2

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k^{2} - 5 k + 2 = 0

k = \frac{5 + 17}{2}, k = \frac{5 - 17}{2}

Decimal Notation

k = 4.56155 \dots, k = 0.43844 \dots

Solution steps

k^{2} - 5 k + 2 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 2 = 17

k_{1, 2} = \frac{- ( - 5 ) \pm 17}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 5 ) + 17}{2 \cdot 1}, k_{2} = \frac{- ( - 5 ) - 17}{2 \cdot 1}

k = \frac{- ( - 5 ) + 17}{2 \cdot 1} : \frac{5 + 17}{2}

k = \frac{- ( - 5 ) - 17}{2 \cdot 1} : \frac{5 - 17}{2}

The solutions to the quadratic equation are:

k = \frac{5 + 17}{2}, k = \frac{5 - 17}{2}

5 x (x + 6) = 0

x^{2} - 12 x + 30 = (x - 1)^{2} + (x - 5)^{2}

6 x^{2} = 11 x - 3

4 v^{2} = - 12 v

\frac{2}{5} x^{2} + 8 x - \frac{9}{4} = \frac{5}{7} x + 15

What are the solutions to the equation k^2-5k+2=0 ?
The solutions to the equation k^2-5k+2=0 are k=(5+sqrt(17))/2 ,k=(5-sqrt(17))/2
Find the zeros of k^2-5k+2=0
The zeros of k^2-5k+2=0 are k=(5+sqrt(17))/2 ,k=(5-sqrt(17))/2