What are the solutions to the equation 7/5 x+7/5 =x^2-8/5 x-13/5 ?

The solutions to the equation 7/5 x+7/5 =x^2-8/5 x-13/5 are x=4,x=-1

Find the zeros of 7/5 x+7/5 =x^2-8/5 x-13/5

The zeros of 7/5 x+7/5 =x^2-8/5 x-13/5 are x=4,x=-1

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\frac{7}{5} x + \frac{7}{5} = x^{2} - \frac{8}{5} x - \frac{13}{5}

x = 4, x = - 1

Solution steps

\frac{7}{5} x + \frac{7}{5} = x^{2} - \frac{8}{5} x - \frac{13}{5}

Multiply both sides by

5

7 x + 7 = 5 x^{2} - 8 x - 13

Switch sides

5 x^{2} - 8 x - 13 = 7 x + 7

Move

7

to the left side

5 x^{2} - 8 x - 20 = 7 x

Move

7 x

to the left side

5 x^{2} - 15 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 5 ( - 20 )}{2 \cdot 5}

(- 15)^{2} - 4 \cdot 5 (- 20) = 25

x_{1, 2} = \frac{- ( - 15 ) \pm 25}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 25}{2 \cdot 5}, x_{2} = \frac{- ( - 15 ) - 25}{2 \cdot 5}

x = \frac{- ( - 15 ) + 25}{2 \cdot 5} : 4

x = \frac{- ( - 15 ) - 25}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

((x - 1) x - 7 x m^{- 1} + 15) = 0

3 q^{2} - q - 12 = - 6

7 - 3 (863 x - 772)^{2} = - 287

x, - 4 y^{3} - 4 x^{2} y + 8 y = 0

12 x^{2} - 36 x - 10 = 0

What are the solutions to the equation 7/5 x+7/5 =x^2-8/5 x-13/5 ?
The solutions to the equation 7/5 x+7/5 =x^2-8/5 x-13/5 are x=4,x=-1
Find the zeros of 7/5 x+7/5 =x^2-8/5 x-13/5
The zeros of 7/5 x+7/5 =x^2-8/5 x-13/5 are x=4,x=-1