What are the solutions to the equation 5x^2-20x+14=2x+6 ?

The solutions to the equation 5x^2-20x+14=2x+6 are x=4,x= 2/5

Find the zeros of 5x^2-20x+14=2x+6

The zeros of 5x^2-20x+14=2x+6 are x=4,x= 2/5

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5 x^{2} - 20 x + 14 = 2 x + 6

x = 4, x = \frac{2}{5}

Decimal Notation

x = 4, x = 0.4

Solution steps

5 x^{2} - 20 x + 14 = 2 x + 6

Move

6

to the left side

5 x^{2} - 20 x + 8 = 2 x

Move

2 x

to the left side

5 x^{2} - 22 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

(- 22)^{2} - 4 \cdot 5 \cdot 8 = 18

x_{1, 2} = \frac{- ( - 22 ) \pm 18}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 18}{2 \cdot 5}, x_{2} = \frac{- ( - 22 ) - 18}{2 \cdot 5}

x = \frac{- ( - 22 ) + 18}{2 \cdot 5} : 4

x = \frac{- ( - 22 ) - 18}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

x = 4, x = \frac{2}{5}

- p^{2} - 63 p + 650 = 62

x^{2} - 20 x + 100 = 0

2 p^{2} - 7 p - 5 = 0

- 15 = \frac{1}{2} (- 9.8) t^{2}

- 2^{2} + y^{2} - 9 = 0

What are the solutions to the equation 5x^2-20x+14=2x+6 ?
The solutions to the equation 5x^2-20x+14=2x+6 are x=4,x= 2/5
Find the zeros of 5x^2-20x+14=2x+6
The zeros of 5x^2-20x+14=2x+6 are x=4,x= 2/5