What are the solutions to the equation 2p^2-7p-5=0 ?

The solutions to the equation 2p^2-7p-5=0 are p=(7+sqrt(89))/4 ,p=(7-sqrt(89))/4

Find the zeros of 2p^2-7p-5=0

The zeros of 2p^2-7p-5=0 are p=(7+sqrt(89))/4 ,p=(7-sqrt(89))/4

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2 p^{2} - 7 p - 5 = 0

p = \frac{7 + 89}{4}, p = \frac{7 - 89}{4}

Decimal Notation

p = 4.10849 \dots, p = - 0.60849 \dots

Solution steps

2 p^{2} - 7 p - 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 5) = 89

p_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 7 ) + 89}{2 \cdot 2}, p_{2} = \frac{- ( - 7 ) - 89}{2 \cdot 2}

p = \frac{- ( - 7 ) + 89}{2 \cdot 2} : \frac{7 + 89}{4}

p = \frac{- ( - 7 ) - 89}{2 \cdot 2} : \frac{7 - 89}{4}

The solutions to the quadratic equation are:

p = \frac{7 + 89}{4}, p = \frac{7 - 89}{4}

- 15 = \frac{1}{2} (- 9.8) t^{2}

- 2^{2} + y^{2} - 9 = 0

x^{2} - 11 x - 10 = 0

4 x^{2} - 10 x + 5 = 0

4 x + 3 = x^{2}

What are the solutions to the equation 2p^2-7p-5=0 ?
The solutions to the equation 2p^2-7p-5=0 are p=(7+sqrt(89))/4 ,p=(7-sqrt(89))/4
Find the zeros of 2p^2-7p-5=0
The zeros of 2p^2-7p-5=0 are p=(7+sqrt(89))/4 ,p=(7-sqrt(89))/4