What are the solutions to the equation w^2+20=-9w ?

The solutions to the equation w^2+20=-9w are w=-4,w=-5

Find the zeros of w^2+20=-9w

The zeros of w^2+20=-9w are w=-4,w=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

w^{2} + 20 = - 9 w

w = - 4, w = - 5

Solution steps

w^{2} + 20 = - 9 w

Move

9 w

to the left side

w^{2} + 20 + 9 w = 0

Write in the standard form

a x^{2} + b x + c = 0

w^{2} + 9 w + 20 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

w_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 9 + 1}{2 \cdot 1}, w_{2} = \frac{- 9 - 1}{2 \cdot 1}

w = \frac{- 9 + 1}{2 \cdot 1} : - 4

w = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

w = - 4, w = - 5

y^{2} + 2 y - 8 y = 0

x^{2} + 1 = 2 x - 1

A (x) = (x + 1)^{2} - 4

6 a^{2} x^{2} - 11 a x = 14

x^{2} - 6 x + 13 = 0

What are the solutions to the equation w^2+20=-9w ?
The solutions to the equation w^2+20=-9w are w=-4,w=-5
Find the zeros of w^2+20=-9w
The zeros of w^2+20=-9w are w=-4,w=-5