What are the solutions to the equation 8y^2-10y-3=0 ?

The solutions to the equation 8y^2-10y-3=0 are y= 3/2 ,y=-1/4

Find the zeros of 8y^2-10y-3=0

The zeros of 8y^2-10y-3=0 are y= 3/2 ,y=-1/4

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8 y^{2} - 10 y - 3 = 0

y = \frac{3}{2}, y = - \frac{1}{4}

Decimal Notation

y = 1.5, y = - 0.25

Solution steps

8 y^{2} - 10 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

(- 10)^{2} - 4 \cdot 8 (- 3) = 14

y_{1, 2} = \frac{- ( - 10 ) \pm 14}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 14}{2 \cdot 8}, y_{2} = \frac{- ( - 10 ) - 14}{2 \cdot 8}

y = \frac{- ( - 10 ) + 14}{2 \cdot 8} : \frac{3}{2}

y = \frac{- ( - 10 ) - 14}{2 \cdot 8} : - \frac{1}{4}

The solutions to the quadratic equation are:

y = \frac{3}{2}, y = - \frac{1}{4}

x, x^{2} + w^{2} = 0

2 m^{2} + m + 128 = 0

a (x) = x (\frac{288 - 2 x}{2})

\frac{x ^{2}}{7} - \frac{x}{14} = \frac{1}{16}

- 9 x^{2} = 108

What are the solutions to the equation 8y^2-10y-3=0 ?
The solutions to the equation 8y^2-10y-3=0 are y= 3/2 ,y=-1/4
Find the zeros of 8y^2-10y-3=0
The zeros of 8y^2-10y-3=0 are y= 3/2 ,y=-1/4