What are the solutions to the equation c^2-3c-10=0 ?

The solutions to the equation c^2-3c-10=0 are c=5,c=-2

Find the zeros of c^2-3c-10=0

The zeros of c^2-3c-10=0 are c=5,c=-2

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c^{2} - 3 c - 10 = 0

c = 5, c = - 2

Solution steps

c^{2} - 3 c - 10 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

c_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, c_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

c = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

c = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

c = 5, c = - 2

x, 2 x^{2} + 2 y^{2} + 12 x - 8 y + 31 = 0

a^{2} = \frac{1}{16}

x^{2} + 6 x - 45 = 2 x

(4 + 2 x) (6 + 2 x) = 24

3 x^{2} - 12 = - 12

What are the solutions to the equation c^2-3c-10=0 ?
The solutions to the equation c^2-3c-10=0 are c=5,c=-2
Find the zeros of c^2-3c-10=0
The zeros of c^2-3c-10=0 are c=5,c=-2