What are the solutions to the equation 2x^2+27x-14=0 ?

The solutions to the equation 2x^2+27x-14=0 are x= 1/2 ,x=-14

Find the zeros of 2x^2+27x-14=0

The zeros of 2x^2+27x-14=0 are x= 1/2 ,x=-14

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2 x^{2} + 27 x - 14 = 0

x = \frac{1}{2}, x = - 14

Decimal Notation

x = 0.5, x = - 14

Solution steps

2 x^{2} + 27 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

2 7^{2} - 4 \cdot 2 (- 14) = 29

x_{1, 2} = \frac{- 27 \pm 29}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 27 + 29}{2 \cdot 2}, x_{2} = \frac{- 27 - 29}{2 \cdot 2}

x = \frac{- 27 + 29}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 27 - 29}{2 \cdot 2} : - 14

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 14

- 6 x = x^{2} + 8

x^{2} + 2 x = - 17

8^{2} + 7^{2} = c^{2}

30 x = 9 x^{2} + 25

12 - r - r^{2} = 0

What are the solutions to the equation 2x^2+27x-14=0 ?
The solutions to the equation 2x^2+27x-14=0 are x= 1/2 ,x=-14
Find the zeros of 2x^2+27x-14=0
The zeros of 2x^2+27x-14=0 are x= 1/2 ,x=-14