What are the solutions to the equation -2n^2-5=-103 ?

The solutions to the equation -2n^2-5=-103 are n=7,n=-7

Find the zeros of -2n^2-5=-103

The zeros of -2n^2-5=-103 are n=7,n=-7

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- 2 n^{2} - 5 = - 103

n = 7, n = - 7

Solution steps

- 2 n^{2} - 5 = - 103

Move

5

to the right side

- 2 n^{2} = - 98

Divide both sides by

- 2

n^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 49, n = - 49

49 = 7

- 49 = - 7

n = 7, n = - 7

x, 4 x^{2} - 3 y^{2} + 12 z^{2} + 12 = 0

x, f (a + h) = 2 x^{2} - 8 x + 6

x, x^{2} + 2 x + y^{2} + 5 = 0

x^{2} + 5 x = 24

5 x^{2} - 2 = 4 x

What are the solutions to the equation -2n^2-5=-103 ?
The solutions to the equation -2n^2-5=-103 are n=7,n=-7
Find the zeros of -2n^2-5=-103
The zeros of -2n^2-5=-103 are n=7,n=-7