What are the solutions to the equation solvefor x,x^2+mx+9=0 ?

The solutions to the equation solvefor x,x^2+mx+9=0 are x=(-m+sqrt(m^2-36))/2 ,x=(-m-sqrt(m^2-36))/2

Find the zeros of solvefor x,x^2+mx+9=0

The zeros of solvefor x,x^2+mx+9=0 are x=(-m+sqrt(m^2-36))/2 ,x=(-m-sqrt(m^2-36))/2

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x, x^{2} + m x + 9 = 0

x = \frac{- m + m ^{2} - 36}{2}, x = \frac{- m - m ^{2} - 36}{2}

Solution steps

x^{2} + m x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- m \pm m ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

m^{2} - 4 \cdot 1 \cdot 9 : m^{2} - 36

x_{1, 2} = \frac{- m \pm m ^{2} - 36}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- m + m ^{2} - 36}{2 \cdot 1}, x_{2} = \frac{- m - m ^{2} - 36}{2 \cdot 1}

x = \frac{- m + m ^{2} - 36}{2 \cdot 1} : \frac{- m + m ^{2} - 36}{2}

x = \frac{- m - m ^{2} - 36}{2 \cdot 1} : \frac{- m - m ^{2} - 36}{2}

The solutions to the quadratic equation are:

x = \frac{- m + m ^{2} - 36}{2}, x = \frac{- m - m ^{2} - 36}{2}

0 = x^{2} - 8 x + 19

- \frac{1}{3} x^{2} - 10 x + 112 = \frac{1}{4} x^{2} + 5 x + 1

x, x^{2} + y^{2} + z^{2} = 2 y

(4 - 4 x + x^{2}) (6 \cdot 1 0^{- 6}) = x^{2} (15 \cdot 1 0^{- 6})

(s - 5) (s + 3) = 0

What are the solutions to the equation solvefor x,x^2+mx+9=0 ?
The solutions to the equation solvefor x,x^2+mx+9=0 are x=(-m+sqrt(m^2-36))/2 ,x=(-m-sqrt(m^2-36))/2
Find the zeros of solvefor x,x^2+mx+9=0
The zeros of solvefor x,x^2+mx+9=0 are x=(-m+sqrt(m^2-36))/2 ,x=(-m-sqrt(m^2-36))/2