What are the solutions to the equation 3x^2-5=-4x ?

The solutions to the equation 3x^2-5=-4x are x=(-2+sqrt(19))/3 ,x=-(2+sqrt(19))/3

Find the zeros of 3x^2-5=-4x

The zeros of 3x^2-5=-4x are x=(-2+sqrt(19))/3 ,x=-(2+sqrt(19))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 5 = - 4 x

x = \frac{- 2 + 19}{3}, x = - \frac{2 + 19}{3}

Decimal Notation

x = 0.78629 \dots, x = - 2.11963 \dots

Solution steps

3 x^{2} - 5 = - 4 x

Move

4 x

to the left side

3 x^{2} - 5 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 5) = 219

x_{1, 2} = \frac{- 4 \pm 2 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 19}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 19}{2 \cdot 3}

x = \frac{- 4 + 2 19}{2 \cdot 3} : \frac{- 2 + 19}{3}

x = \frac{- 4 - 2 19}{2 \cdot 3} : - \frac{2 + 19}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 19}{3}, x = - \frac{2 + 19}{3}

2 x^{2} + 7 x + 12 = 0

y, (c y^{2}) (4 y d) = - 20 y^{3}

(x) = x^{2} - 1

p^{2} - 8 p + 12 = 0

2 x^{2} + 35 = 1315 - 3 x^{2}

What are the solutions to the equation 3x^2-5=-4x ?
The solutions to the equation 3x^2-5=-4x are x=(-2+sqrt(19))/3 ,x=-(2+sqrt(19))/3
Find the zeros of 3x^2-5=-4x
The zeros of 3x^2-5=-4x are x=(-2+sqrt(19))/3 ,x=-(2+sqrt(19))/3