What are the solutions to the equation u^2+7u+6=0 ?

The solutions to the equation u^2+7u+6=0 are u=-1,u=-6

Find the zeros of u^2+7u+6=0

The zeros of u^2+7u+6=0 are u=-1,u=-6

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u^{2} + 7 u + 6 = 0

u = - 1, u = - 6

Solution steps

u^{2} + 7 u + 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

u_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 7 + 5}{2 \cdot 1}, u_{2} = \frac{- 7 - 5}{2 \cdot 1}

u = \frac{- 7 + 5}{2 \cdot 1} : - 1

u = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

u = - 1, u = - 6

p, 3 p = 10 - p^{2}

z^{2} = - 9

x, 2 y^{2} + x y - x^{2} = c

z^{2} + 4 z + 8 = 0

x^{2} + (\frac{5}{6})^{2} = 1

What are the solutions to the equation u^2+7u+6=0 ?
The solutions to the equation u^2+7u+6=0 are u=-1,u=-6
Find the zeros of u^2+7u+6=0
The zeros of u^2+7u+6=0 are u=-1,u=-6