What are the solutions to the equation s^2+6s+4=0 ?

The solutions to the equation s^2+6s+4=0 are s=-3+sqrt(5),s=-3-sqrt(5)

Find the zeros of s^2+6s+4=0

The zeros of s^2+6s+4=0 are s=-3+sqrt(5),s=-3-sqrt(5)

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s^{2} + 6 s + 4 = 0

s = - 3 + 5, s = - 3 - 5

Decimal Notation

s = - 0.76393 \dots, s = - 5.23606 \dots

Solution steps

s^{2} + 6 s + 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 4 = 25

s_{1, 2} = \frac{- 6 \pm 2 5}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 6 + 2 5}{2 \cdot 1}, s_{2} = \frac{- 6 - 2 5}{2 \cdot 1}

s = \frac{- 6 + 2 5}{2 \cdot 1} : - 3 + 5

s = \frac{- 6 - 2 5}{2 \cdot 1} : - 3 - 5

The solutions to the quadratic equation are:

s = - 3 + 5, s = - 3 - 5

2 (5) - 3

\frac{1}{2} x = x

2 (x - 1) (x + 2) = 0

\frac{x ^{- 8} y ^{- 6} y ^{5}}{x ^{- 3}}

z^{4} + (\frac{i + 2 + i}{1 + i \cdot ( 2 + i )})^{3} \cdot (- i)

What are the solutions to the equation s^2+6s+4=0 ?
The solutions to the equation s^2+6s+4=0 are s=-3+sqrt(5),s=-3-sqrt(5)
Find the zeros of s^2+6s+4=0
The zeros of s^2+6s+4=0 are s=-3+sqrt(5),s=-3-sqrt(5)