What are the solutions to the equation 25^2=7^2+b^2 ?

The solutions to the equation 25^2=7^2+b^2 are b=24,b=-24

Find the zeros of 25^2=7^2+b^2

The zeros of 25^2=7^2+b^2 are b=24,b=-24

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2 5^{2} = 7^{2} + b^{2}

b = 24, b = - 24

Solution steps

2 5^{2} = 7^{2} + b^{2}

Switch sides

7^{2} + b^{2} = 2 5^{2}

Move

7^{2}

to the right side

b^{2} = 576

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 576, b = - 576

576 = 24

- 576 = - 24

b = 24, b = - 24

2 x^{2} - 2 x + 1

- 26 = - x^{2} - 1

9 (x^{2} + 1) = 34

\frac{x ^{2}}{2} = 7 x

x^{2} - 3 x + (- \frac{9}{4}) = 12

What are the solutions to the equation 25^2=7^2+b^2 ?
The solutions to the equation 25^2=7^2+b^2 are b=24,b=-24
Find the zeros of 25^2=7^2+b^2
The zeros of 25^2=7^2+b^2 are b=24,b=-24