What are the solutions to the equation 2x^2-6x=-9 ?

The solutions to the equation 2x^2-6x=-9 are x= 3/2+i 3/2 ,x= 3/2-i 3/2

Find the zeros of 2x^2-6x=-9

The zeros of 2x^2-6x=-9 are x= 3/2+i 3/2 ,x= 3/2-i 3/2

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2 x^{2} - 6 x = - 9

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

Solution steps

2 x^{2} - 6 x = - 9

Move

9

to the left side

2 x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 9 : 6 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 i}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 6 i}{2 \cdot 2}

x = \frac{- ( - 6 ) + 6 i}{2 \cdot 2} : \frac{3}{2} + i \frac{3}{2}

x = \frac{- ( - 6 ) - 6 i}{2 \cdot 2} : \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

3 u^{2} - 4 u + 1 = 0

x, x^{2} + y^{2} + z^{2} = y

10 x^{2} - 130 x + 400 = 0

5 x^{2} = 9

a^{2} - 13 a - 62 = 0

What are the solutions to the equation 2x^2-6x=-9 ?
The solutions to the equation 2x^2-6x=-9 are x= 3/2+i 3/2 ,x= 3/2-i 3/2
Find the zeros of 2x^2-6x=-9
The zeros of 2x^2-6x=-9 are x= 3/2+i 3/2 ,x= 3/2-i 3/2