What are the solutions to the equation x^2+6x-41=6x-56x-5 ?

The solutions to the equation x^2+6x-41=6x-56x-5 are x=2(sqrt(205)-14),x=-2(14+sqrt(205))

Find the zeros of x^2+6x-41=6x-56x-5

The zeros of x^2+6x-41=6x-56x-5 are x=2(sqrt(205)-14),x=-2(14+sqrt(205))

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x^{2} + 6 x - 41 = 6 x - 56 x - 5

x = 2 (205 - 14), x = - 2 (14 + 205)

Decimal Notation

x = 0.63564 \dots, x = - 56.63564 \dots

Solution steps

x^{2} + 6 x - 41 = 6 x - 56 x - 5

Refine

x^{2} + 6 x - 41 = - 50 x - 5

Move

5

to the left side

x^{2} + 6 x - 36 = - 50 x

Move

50 x

to the left side

x^{2} + 56 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

5 6^{2} - 4 \cdot 1 \cdot (- 36) = 4205

x_{1, 2} = \frac{- 56 \pm 4 205}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 56 + 4 205}{2 \cdot 1}, x_{2} = \frac{- 56 - 4 205}{2 \cdot 1}

x = \frac{- 56 + 4 205}{2 \cdot 1} : 2 (205 - 14)

x = \frac{- 56 - 4 205}{2 \cdot 1} : - 2 (14 + 205)

The solutions to the quadratic equation are:

x = 2 (205 - 14), x = - 2 (14 + 205)

3 y^{2} - 11 y + 10 = 0

(4 a - 7) (3 a + 8) = 0

x, 4 x^{2} = y^{2}

8000 + 55 x - 0.25 x^{2} = 9000

2 x^{2} - 4 x + 30 = 0

What are the solutions to the equation x^2+6x-41=6x-56x-5 ?
The solutions to the equation x^2+6x-41=6x-56x-5 are x=2(sqrt(205)-14),x=-2(14+sqrt(205))
Find the zeros of x^2+6x-41=6x-56x-5
The zeros of x^2+6x-41=6x-56x-5 are x=2(sqrt(205)-14),x=-2(14+sqrt(205))