What are the solutions to the equation y^2+16y-36=0 ?

The solutions to the equation y^2+16y-36=0 are y=2,y=-18

Find the zeros of y^2+16y-36=0

The zeros of y^2+16y-36=0 are y=2,y=-18

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y^{2} + 16 y - 36 = 0

y = 2, y = - 18

Solution steps

y^{2} + 16 y - 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 36) = 20

y_{1, 2} = \frac{- 16 \pm 20}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 16 + 20}{2 \cdot 1}, y_{2} = \frac{- 16 - 20}{2 \cdot 1}

y = \frac{- 16 + 20}{2 \cdot 1} : 2

y = \frac{- 16 - 20}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

y = 2, y = - 18

2 (x - 1)^{2} = 32

w = 2 w^{2} - 1

15 = 0 t + (\frac{1}{2}) (9.81) t^{2}

x^{2} = 0.5 x + 3

49 x^{2} - 11 = 110

What are the solutions to the equation y^2+16y-36=0 ?
The solutions to the equation y^2+16y-36=0 are y=2,y=-18
Find the zeros of y^2+16y-36=0
The zeros of y^2+16y-36=0 are y=2,y=-18