What are the solutions to the equation 2x^2-23x-43=0 ?

The solutions to the equation 2x^2-23x-43=0 are x=(23+3sqrt(97))/4 ,x=(23-3sqrt(97))/4

Find the zeros of 2x^2-23x-43=0

The zeros of 2x^2-23x-43=0 are x=(23+3sqrt(97))/4 ,x=(23-3sqrt(97))/4

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2 x^{2} - 23 x - 43 = 0

x = \frac{23 + 3 97}{4}, x = \frac{23 - 3 97}{4}

Decimal Notation

x = 13.13664 \dots, x = - 1.63664 \dots

Solution steps

2 x^{2} - 23 x - 43 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 2 ( - 43 )}{2 \cdot 2}

(- 23)^{2} - 4 \cdot 2 (- 43) = 397

x_{1, 2} = \frac{- ( - 23 ) \pm 3 97}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 3 97}{2 \cdot 2}, x_{2} = \frac{- ( - 23 ) - 3 97}{2 \cdot 2}

x = \frac{- ( - 23 ) + 3 97}{2 \cdot 2} : \frac{23 + 3 97}{4}

x = \frac{- ( - 23 ) - 3 97}{2 \cdot 2} : \frac{23 - 3 97}{4}

The solutions to the quadratic equation are:

x = \frac{23 + 3 97}{4}, x = \frac{23 - 3 97}{4}

u^{2} - 6 u + 5 = 0

x, f = (3 m - 6) 3 x^{2} + 5 x + 8

3 x^{2} + 12 x - 1 = 0

x^{2} + 3 x - 1 = 0

3 x^{2} + 2 x - 7

What are the solutions to the equation 2x^2-23x-43=0 ?
The solutions to the equation 2x^2-23x-43=0 are x=(23+3sqrt(97))/4 ,x=(23-3sqrt(97))/4
Find the zeros of 2x^2-23x-43=0
The zeros of 2x^2-23x-43=0 are x=(23+3sqrt(97))/4 ,x=(23-3sqrt(97))/4