What are the solutions to the equation X^2+8X+16=0 ?

The solutions to the equation X^2+8X+16=0 are X=-4

Find the zeros of X^2+8X+16=0

The zeros of X^2+8X+16=0 are X=-4

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X^{2} + 8 X + 16 = 0

X = - 4

Solution steps

X^{2} + 8 X + 16 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

X_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

X = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

X = - 4

The solution to the quadratic equation is:

X = - 4

x^{2} + 4 x + \frac{1}{2} = 0

x, z = 4 x^{2} + y^{2} + 1

\frac{1}{8} (5 r)^{2} π - π (3 r)^{2} \frac{1}{8} = \frac{81}{2} π

x, x^{2} + m^{2} = 0

2 x^{2} + 4 x + 4 = 100

What are the solutions to the equation X^2+8X+16=0 ?
The solutions to the equation X^2+8X+16=0 are X=-4
Find the zeros of X^2+8X+16=0
The zeros of X^2+8X+16=0 are X=-4