What are the solutions to the equation 3n^2-7n+2=0 ?

The solutions to the equation 3n^2-7n+2=0 are n=2,n= 1/3

Find the zeros of 3n^2-7n+2=0

The zeros of 3n^2-7n+2=0 are n=2,n= 1/3

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3 n^{2} - 7 n + 2 = 0

n = 2, n = \frac{1}{3}

Decimal Notation

n = 2, n = 0.33333 \dots

Solution steps

3 n^{2} - 7 n + 2 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 2 = 5

n_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 3}, n_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 3}

n = \frac{- ( - 7 ) + 5}{2 \cdot 3} : 2

n = \frac{- ( - 7 ) - 5}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

n = 2, n = \frac{1}{3}

(x - 5)^{2} - 13 = 0

x^{2} + 13 x - 54 = 10 x

3 x + x^{2} = 40

x [x - 3 (12 - 3 x) + 2 x] = 5 (2 x^{2} - 1)

10 x - 15 x^{2} = 0

What are the solutions to the equation 3n^2-7n+2=0 ?
The solutions to the equation 3n^2-7n+2=0 are n=2,n= 1/3
Find the zeros of 3n^2-7n+2=0
The zeros of 3n^2-7n+2=0 are n=2,n= 1/3