What are the solutions to the equation -1=5x^2-2x ?

The solutions to the equation -1=5x^2-2x are x= 1/5+i 2/5 ,x= 1/5-i 2/5

Find the zeros of -1=5x^2-2x

The zeros of -1=5x^2-2x are x= 1/5+i 2/5 ,x= 1/5-i 2/5

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- 1 = 5 x^{2} - 2 x

x = \frac{1}{5} + i \frac{2}{5}, x = \frac{1}{5} - i \frac{2}{5}

Solution steps

- 1 = 5 x^{2} - 2 x

Switch sides

5 x^{2} - 2 x = - 1

Move

1

to the left side

5 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

Simplify

(- 2)^{2} - 4 \cdot 5 \cdot 1 : 4 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 5}

x = \frac{- ( - 2 ) + 4 i}{2 \cdot 5} : \frac{1}{5} + i \frac{2}{5}

x = \frac{- ( - 2 ) - 4 i}{2 \cdot 5} : \frac{1}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5} + i \frac{2}{5}, x = \frac{1}{5} - i \frac{2}{5}

t, f = (a - b t)^{2}

2 u^{2} - 3 u - 2 = 0

x^{2} + (- 5) x + 6 = 0

x, x^{2} + y^{2} = 1 - \frac{3}{2} x y

6 x^{2} = 3 x^{2} - 3

What are the solutions to the equation -1=5x^2-2x ?
The solutions to the equation -1=5x^2-2x are x= 1/5+i 2/5 ,x= 1/5-i 2/5
Find the zeros of -1=5x^2-2x
The zeros of -1=5x^2-2x are x= 1/5+i 2/5 ,x= 1/5-i 2/5