What are the solutions to the equation 1/4 (7-4x^2)+4x+(1-8x)/2 =0 ?

The solutions to the equation 1/4 (7-4x^2)+4x+(1-8x)/2 =0 are x=-3/2 ,x= 3/2

Find the zeros of 1/4 (7-4x^2)+4x+(1-8x)/2 =0

The zeros of 1/4 (7-4x^2)+4x+(1-8x)/2 =0 are x=-3/2 ,x= 3/2

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\frac{1}{4} (7 - 4 x^{2}) + 4 x + \frac{1 - 8 x}{2} = 0

x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = - 1.5, x = 1.5

Solution steps

\frac{1}{4} (7 - 4 x^{2}) + 4 x + \frac{1 - 8 x}{2} = 0

Find Least Common Multiplier of

4, 2 : 4

Multiply by LCM=

4

\frac{1}{4} (7 - 4 x^{2}) \cdot 4 + 4 x \cdot 4 + \frac{1 - 8 x}{2} \cdot 4 = 0 \cdot 4

Simplify

7 - 4 x^{2} + 16 x + 2 (- 8 x + 1) = 0

Expand

7 - 4 x^{2} + 16 x + 2 (- 8 x + 1) : - 4 x^{2} + 9

- 4 x^{2} + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 ( - 4 ) \cdot 9}{2 ( - 4 )}

0^{2} - 4 (- 4) \cdot 9 = 12

x_{1, 2} = \frac{- 0 \pm 12}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 0 + 12}{2 ( - 4 )}, x_{2} = \frac{- 0 - 12}{2 ( - 4 )}

x = \frac{- 0 + 12}{2 ( - 4 )} : - \frac{3}{2}

x = \frac{- 0 - 12}{2 ( - 4 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = \frac{3}{2}

x, x^{2} = 4 y^{2}

- 3 x^{2} + 12 x + 6 = 0

2 a^{2} + 3 a + 1 = 0

2 (x + 1.5 x)^{2} - 7.5 = 0

3 x^{2} - 3 x + 7 = 9 x + 3

What are the solutions to the equation 1/4 (7-4x^2)+4x+(1-8x)/2 =0 ?
The solutions to the equation 1/4 (7-4x^2)+4x+(1-8x)/2 =0 are x=-3/2 ,x= 3/2
Find the zeros of 1/4 (7-4x^2)+4x+(1-8x)/2 =0
The zeros of 1/4 (7-4x^2)+4x+(1-8x)/2 =0 are x=-3/2 ,x= 3/2