What are the solutions to the equation (3x+5)^2=4 ?

The solutions to the equation (3x+5)^2=4 are x=-1,x=-7/3

Find the zeros of (3x+5)^2=4

The zeros of (3x+5)^2=4 are x=-1,x=-7/3

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(3 x + 5)^{2} = 4

x = - 1, x = - \frac{7}{3}

Decimal Notation

x = - 1, x = - 2.33333 \dots

Solution steps

(3 x + 5)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 5 = 4 : x = - 1

Solve

3 x + 5 = - 4 : x = - \frac{7}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{7}{3}

2 (5 x - 4) = (x + 4) (4 - x)

4.9 x^{2} - 42 x + 80 = 0

a x^{2} + 9 a x + 20 = 0

4 x = - 5 x^{2} - 1

90 = - 3.7829 x^{2} + 35.044 x - 1.4862

What are the solutions to the equation (3x+5)^2=4 ?
The solutions to the equation (3x+5)^2=4 are x=-1,x=-7/3
Find the zeros of (3x+5)^2=4
The zeros of (3x+5)^2=4 are x=-1,x=-7/3