What are the solutions to the equation 1+6x+9x^2=0 ?

The solutions to the equation 1+6x+9x^2=0 are x=-1/3

Find the zeros of 1+6x+9x^2=0

The zeros of 1+6x+9x^2=0 are x=-1/3

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1 + 6 x + 9 x^{2} = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

1 + 6 x + 9 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

x = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

x = - \frac{1}{3}

The solution to the quadratic equation is:

x = - \frac{1}{3}

p = \frac{400 - p ^{2}}{60} + 5

x^{2} + 18 x - 18 = 0

3 a^{2} - 6 a - 16 = 0

x^{2} = 13 x - 40

\frac{n ( n - 3 )}{2} + 63 = \frac{2 n ( 2 n - 3 )}{2}

What are the solutions to the equation 1+6x+9x^2=0 ?
The solutions to the equation 1+6x+9x^2=0 are x=-1/3
Find the zeros of 1+6x+9x^2=0
The zeros of 1+6x+9x^2=0 are x=-1/3