What are the solutions to the equation 24^2+x^2=40^2 ?

The solutions to the equation 24^2+x^2=40^2 are x=32,x=-32

Find the zeros of 24^2+x^2=40^2

The zeros of 24^2+x^2=40^2 are x=32,x=-32

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2 4^{2} + x^{2} = 4 0^{2}

x = 32, x = - 32

Solution steps

2 4^{2} + x^{2} = 4 0^{2}

Move

2 4^{2}

to the right side

x^{2} = 1024

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1024, x = - 1024

1024 = 32

- 1024 = - 32

x = 32, x = - 32

[x^{2} - x + 3] = 5

3 u^{2} - 15 u + 12 = 0

t^{2} - t - 6 = - 4

0 = 10 - 12 t^{2}

x^{2} + \frac{3}{2} x

What are the solutions to the equation 24^2+x^2=40^2 ?
The solutions to the equation 24^2+x^2=40^2 are x=32,x=-32
Find the zeros of 24^2+x^2=40^2
The zeros of 24^2+x^2=40^2 are x=32,x=-32