What are the solutions to the equation (x+5)x=104 ?

The solutions to the equation (x+5)x=104 are x=8,x=-13

Find the zeros of (x+5)x=104

The zeros of (x+5)x=104 are x=8,x=-13

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(x + 5) x = 104

x = 8, x = - 13

Solution steps

(x + 5) x = 104

Expand

(x + 5) x : x^{2} + 5 x

x^{2} + 5 x = 104

Move

104

to the left side

x^{2} + 5 x - 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 104 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 104) = 21

x_{1, 2} = \frac{- 5 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 21}{2 \cdot 1}, x_{2} = \frac{- 5 - 21}{2 \cdot 1}

x = \frac{- 5 + 21}{2 \cdot 1} : 8

x = \frac{- 5 - 21}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 8, x = - 13

lo g_{10} (2) x^{2} + 2 = 6

- 2 x^{2} + 10 x = - 14

d^{2} - d - 56 = 0

r^{2} + 8 r + 208 = 0

r (r - 1) = 0

What are the solutions to the equation (x+5)x=104 ?
The solutions to the equation (x+5)x=104 are x=8,x=-13
Find the zeros of (x+5)x=104
The zeros of (x+5)x=104 are x=8,x=-13