What are the solutions to the equation (2x+15)(9+2x)-(15)(9)=100 ?

The solutions to the equation (2x+15)(9+2x)-(15)(9)=100 are x=-6+sqrt(61),x=-6-sqrt(61)

Find the zeros of (2x+15)(9+2x)-(15)(9)=100

The zeros of (2x+15)(9+2x)-(15)(9)=100 are x=-6+sqrt(61),x=-6-sqrt(61)

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(2 x + 15) (9 + 2 x) - (15) (9) = 100

x = - 6 + 61, x = - 6 - 61

Decimal Notation

x = 1.81024 \dots, x = - 13.81024 \dots

Solution steps

(2 x + 15) (9 + 2 x) - (15) (9) = 100

Expand

(2 x + 15) (9 + 2 x) - (15) (9) : 4 x^{2} + 48 x

4 x^{2} + 48 x = 100

Move

100

to the left side

4 x^{2} + 48 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 4 ( - 100 )}{2 \cdot 4}

4 8^{2} - 4 \cdot 4 (- 100) = 861

x_{1, 2} = \frac{- 48 \pm 8 61}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 48 + 8 61}{2 \cdot 4}, x_{2} = \frac{- 48 - 8 61}{2 \cdot 4}

x = \frac{- 48 + 8 61}{2 \cdot 4} : - 6 + 61

x = \frac{- 48 - 8 61}{2 \cdot 4} : - 6 - 61

The solutions to the quadratic equation are:

x = - 6 + 61, x = - 6 - 61

x^{2} + 8 (\frac{- 8 - 3 x}{4}) = 0

(x + 6)^{2} + 3 (5 x - 6) = - 2 (x^{2} + x)

X^{2} + X - 1 = 3 (X - 4)^{2} + 2

lo g_{10} (4) (x^{2} - 2) = \frac{1}{2}

x^{2} - 10 x + 20 = - 4

What are the solutions to the equation (2x+15)(9+2x)-(15)(9)=100 ?
The solutions to the equation (2x+15)(9+2x)-(15)(9)=100 are x=-6+sqrt(61),x=-6-sqrt(61)
Find the zeros of (2x+15)(9+2x)-(15)(9)=100
The zeros of (2x+15)(9+2x)-(15)(9)=100 are x=-6+sqrt(61),x=-6-sqrt(61)