What are the solutions to the equation 2x^2+9-10=0 ?

The solutions to the equation 2x^2+9-10=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 2x^2+9-10=0

The zeros of 2x^2+9-10=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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2 x^{2} + 9 - 10 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

2 x^{2} + 9 - 10 = 0

Move

9

to the right side

2 x^{2} - 10 = - 9

Move

10

to the right side

2 x^{2} = 1

Divide both sides by

2

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

- 5 x^{2} - 40 x + 45 = 0

2 x^{2} - 8 x + 4

- \frac{1.85}{20.25} x^{2} + \frac{1.85}{20.25} x + 1.82716049

x, x^{2} - 4 x y + 5 y^{2} - 4 y + 4 = 0

x, F = 2 x y^{2} x + (y + 2 y x^{2}) y

What are the solutions to the equation 2x^2+9-10=0 ?
The solutions to the equation 2x^2+9-10=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 2x^2+9-10=0
The zeros of 2x^2+9-10=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))