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Popular >

λ^2-4λ+3=0

Solution

λ^{2} - 4 λ + 3 = 0

Solution

λ = 3, λ = 1

Solution steps

λ^{2} - 4 λ + 3 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

λ_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, λ_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

λ = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

λ = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

λ = 3, λ = 1

Popular Examples

solvefor x,x^2y-4y+4=0 solve for

x, x^{2} y - 4 y + 4 = 0

(x - 3)^{3} = x^{3} + 5

solvefor b,V= 1/3 b^2h solve for

b, V = \frac{1}{3} b^{2} h

x^{2} + 1 = 10 (3 x - 8)

(-4s+1/2)(-4/5 s-4)=0,(-4s+21)(-54s-4)=0

(- 4 s + \frac{1}{2}) (- \frac{4}{5} s - 4) = 0, (- 4 s + 21) (- 54 s - 4) = 0

Frequently Asked Questions (FAQ)

What are the solutions to the equation λ^2-4λ+3=0 ?
The solutions to the equation λ^2-4λ+3=0 are λ=3,λ=1
Find the zeros of λ^2-4λ+3=0
The zeros of λ^2-4λ+3=0 are λ=3,λ=1