What are the solutions to the equation -0.2x^2+5x-20=0 ?

The solutions to the equation -0.2x^2+5x-20=0 are x=5,x=20

Find the zeros of -0.2x^2+5x-20=0

The zeros of -0.2x^2+5x-20=0 are x=5,x=20

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- 0.2 x^{2} + 5 x - 20 = 0

x = 5, x = 20

Solution steps

- 0.2 x^{2} + 5 x - 20 = 0

Multiply both sides by

10

- 2 x^{2} + 50 x - 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 2 ) ( - 200 )}{2 ( - 2 )}

5 0^{2} - 4 (- 2) (- 200) = 30

x_{1, 2} = \frac{- 50 \pm 30}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 50 + 30}{2 ( - 2 )}, x_{2} = \frac{- 50 - 30}{2 ( - 2 )}

x = \frac{- 50 + 30}{2 ( - 2 )} : 5

x = \frac{- 50 - 30}{2 ( - 2 )} : 20

The solutions to the quadratic equation are:

x = 5, x = 20

u^{2} + u + 1 = 0

9 x^{2} + 18 x

z^{2} - 49 = 0

- 2 x^{2} + 10 x - 8 = 0

(a - 4)^{2} = 16

What are the solutions to the equation -0.2x^2+5x-20=0 ?
The solutions to the equation -0.2x^2+5x-20=0 are x=5,x=20
Find the zeros of -0.2x^2+5x-20=0
The zeros of -0.2x^2+5x-20=0 are x=5,x=20