What are the solutions to the equation A=(x+8)^2+(x-8)^2-(x+2)(x-2) ?

The solutions to the equation A=(x+8)^2+(x-8)^2-(x+2)(x-2) are x=sqrt(A-132),x=-sqrt(A-132)

Find the zeros of A=(x+8)^2+(x-8)^2-(x+2)(x-2)

The zeros of A=(x+8)^2+(x-8)^2-(x+2)(x-2) are x=sqrt(A-132),x=-sqrt(A-132)

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A = (x + 8)^{2} + (x - 8)^{2} - (x + 2) (x - 2)

x = A - 132, x = - A - 132

Solution steps

A = (x + 8)^{2} + (x - 8)^{2} - (x + 2) (x - 2)

Expand

(x + 8)^{2} + (x - 8)^{2} - (x + 2) (x - 2) : x^{2} + 132

A = x^{2} + 132

Switch sides

x^{2} + 132 = A

Move

A

to the left side

x^{2} + 132 - A = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( 132 - A )}{2 \cdot 1}

Simplify

0^{2} - 4 \cdot 1 \cdot (132 - A) : 2 A - 132

x_{1, 2} = \frac{- 0 \pm 2 A - 132}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 2 A - 132}{2 \cdot 1}, x_{2} = \frac{- 0 - 2 A - 132}{2 \cdot 1}

x = \frac{- 0 + 2 A - 132}{2 \cdot 1} : A - 132

x = \frac{- 0 - 2 A - 132}{2 \cdot 1} : - A - 132

The solutions to the quadratic equation are:

x = A - 132, x = - A - 132

x^{2} - 3 x - 1 = 0

2 x (x - 4) = 12

2 x^{2} - 2 x - 30 = - 2 x^{2} - 19

v^{2} - 4 v - 12 = 0

- x^{2} - x + 6 = 0

What are the solutions to the equation A=(x+8)^2+(x-8)^2-(x+2)(x-2) ?
The solutions to the equation A=(x+8)^2+(x-8)^2-(x+2)(x-2) are x=sqrt(A-132),x=-sqrt(A-132)
Find the zeros of A=(x+8)^2+(x-8)^2-(x+2)(x-2)
The zeros of A=(x+8)^2+(x-8)^2-(x+2)(x-2) are x=sqrt(A-132),x=-sqrt(A-132)