What are the solutions to the equation 9x^2+12x+13=0 ?

The solutions to the equation 9x^2+12x+13=0 are x=-2/3+i,x=-2/3-i

Find the zeros of 9x^2+12x+13=0

The zeros of 9x^2+12x+13=0 are x=-2/3+i,x=-2/3-i

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9 x^{2} + 12 x + 13 = 0

x = - \frac{2}{3} + i, x = - \frac{2}{3} - i

Solution steps

9 x^{2} + 12 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 \cdot 13}{2 \cdot 9}

Simplify

1 2^{2} - 4 \cdot 9 \cdot 13 : 18 i

x_{1, 2} = \frac{- 12 \pm 18 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 12 + 18 i}{2 \cdot 9}, x_{2} = \frac{- 12 - 18 i}{2 \cdot 9}

x = \frac{- 12 + 18 i}{2 \cdot 9} : - \frac{2}{3} + i

x = \frac{- 12 - 18 i}{2 \cdot 9} : - \frac{2}{3} - i

The solutions to the quadratic equation are:

x = - \frac{2}{3} + i, x = - \frac{2}{3} - i

r^{2} - 12 r + 52 = 0

- x^{2} + 5 x

x^{2} - 87 x + 1180 = 0

t^{2} + 22 t = - 27

(3 n - 1) \cdot x^{2} - (5 n + 2) \cdot x + 2 = 0

What are the solutions to the equation 9x^2+12x+13=0 ?
The solutions to the equation 9x^2+12x+13=0 are x=-2/3+i,x=-2/3-i
Find the zeros of 9x^2+12x+13=0
The zeros of 9x^2+12x+13=0 are x=-2/3+i,x=-2/3-i