What are the solutions to the equation c^2-6=-c ?

The solutions to the equation c^2-6=-c are c=2,c=-3

Find the zeros of c^2-6=-c

The zeros of c^2-6=-c are c=2,c=-3

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c^{2} - 6 = - c

c = 2, c = - 3

Solution steps

c^{2} - 6 = - c

Move

c

to the left side

c^{2} - 6 + c = 0

Write in the standard form

a x^{2} + b x + c = 0

c^{2} + c - 6 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

c_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 1 + 5}{2 \cdot 1}, c_{2} = \frac{- 1 - 5}{2 \cdot 1}

c = \frac{- 1 + 5}{2 \cdot 1} : 2

c = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

c = 2, c = - 3

3 x^{2} - 12 x - 8 = 0

27 + 20 x (x - 2) = (5 x - 4)^{2} - (3 x + 5) (2 x - 1)

y^{2} + y = - 1

10 x^{2} + 4 x = - 9

x^{2} - 1 x - 90 = 0

What are the solutions to the equation c^2-6=-c ?
The solutions to the equation c^2-6=-c are c=2,c=-3
Find the zeros of c^2-6=-c
The zeros of c^2-6=-c are c=2,c=-3